Răspuns :
fie a,b,c măsuril unghiurilor
a,b,c dp 10,4,6 => a = 10 k , b = 4 k , c = 6 k .
a+b+c = 180
10k+4k+6k = 180
k = 9 .
a = 10*9 = 90 gr
b = 4*9 = 36gr
c = 6*9 = 54gr .
⇒ triunghiul este dreptunghic
a,b,c dp 10,4,6 => a = 10 k , b = 4 k , c = 6 k .
a+b+c = 180
10k+4k+6k = 180
k = 9 .
a = 10*9 = 90 gr
b = 4*9 = 36gr
c = 6*9 = 54gr .
⇒ triunghiul este dreptunghic
a,b,c dp 10,4,6 (a,b,c-masurile unghiurilor Δ)
a/10=b/4=c/6=k
a=10k
b=4k
c=6k
10k+4k+6k=180
20k=180
k=9
a=9*10=90 grade <=>ΔABC-dreptunghic , mas<A=90 grade
b=4*9=36 grade
c=6*9=54 grade
a/10=b/4=c/6=k
a=10k
b=4k
c=6k
10k+4k+6k=180
20k=180
k=9
a=9*10=90 grade <=>ΔABC-dreptunghic , mas<A=90 grade
b=4*9=36 grade
c=6*9=54 grade