Răspuns :
P=caz favorabile/caz posibile=m/n
a) P=4/6=0.6666
b)P=2/6=0.3333
c) AVem nr pare 2,4,6 P=3/6=0.5
d)avem nr impare 1 ,3,5 P=3/6=0,5
e)Nr divizibile la 3 sunt 3 ,6 P=2/6=0.33333
f)P=3/6=0.5
g)Patarat perfect 4=2^2 P=1/6=0.16666
h)Nr prime sunt 2,3,5 P=3/6=0.5
a) P=4/6=0.6666
b)P=2/6=0.3333
c) AVem nr pare 2,4,6 P=3/6=0.5
d)avem nr impare 1 ,3,5 P=3/6=0,5
e)Nr divizibile la 3 sunt 3 ,6 P=2/6=0.33333
f)P=3/6=0.5
g)Patarat perfect 4=2^2 P=1/6=0.16666
h)Nr prime sunt 2,3,5 P=3/6=0.5
probabilitatea =nr cazurilor favorabile/nr cazurilor posibile
a)p=1/6
b)p=1/6
c)p= 3/6=1/2
d)p=3/6=1/2
e)p= 2/6=1/3
f)p=3/6=1/2
g)p=2/6=13
h)p=4/6=2/3
a)p=1/6
b)p=1/6
c)p= 3/6=1/2
d)p=3/6=1/2
e)p= 2/6=1/3
f)p=3/6=1/2
g)p=2/6=13
h)p=4/6=2/3