Răspuns :

Miky93id
ABCD-romb
AB=BC=DC=AD
BD intersectat AC={O}

ΔABD
AB=BD=6
AB=AD              =>ΔABD-echilateral

fie [AO_|_ BD
AO-h

AO=l√3/2=  6√3/2=  3√3

AO=OC=AC/2  =>AC=2*AO=2*3√3=6√3

ID Alte intrebari