1 a) H2SO4 + 2 NaOH ---> Na2SO4 + 2 H2O
1 mol H2SO4......2 moli NaOH
0,1 moli H2SO4.......x moli NaOH x = 0,2 moli NaOH
nr moli = masa NaOH/masa molara NaOH => m NaOH = 0.2*40 = 8 g NaOH
b) Na + 1/2 Cl2 ---> NaCl
1/2 moli Cl2.......58,5 g NaCl
0,2 moli Cl2...........x g NaCl x = 23,4 g NaCl
2 a) nr moli 1 = 0.2 * 0,1 = 0.02 moli => m KOH = 0,02 * 56 = 1,12 g KOH
nr moli 2 = 0.1 * 0,2 = 0,02 moli => m KOH = 0,02 * 56 = 1,12 g KOH
=> nr moli KOH total = 0,02+0,02 = 0,04 moli
=> cM = nr moli KOH total/volum total = 0,04/(0.1+0,2+0,1)=> cM = 0,1 M
Aditional - pOH = - lg [cM] = - lg 10 la -1 = 1 => pH = 14-pOH = 14-1 = 13 (bonus)