Oana20id Oana20id Matematică a fost răspuns 1.calculati a·b,daca: a) a=3√48 - 4√18 - 5√108 + 6√72 si b=2√162 + 5√75 - 2√50 - 11√12 b) a=√48 - √108 + √192 - √243 + √147 si b=√45 - √80 + √180 - √320 + √125 c) a=√32 - √72 + √128 - √162 + √50 si b=√150 - √384 + √54 - √24 + √96 2.calculati media a numerelor: a) x=(√3 + √2) (√7 -√6) ; y=(√3 -√2) (√7 + √6) b) x=(√5 - √4) (√6 + √5) (√7- √3) ; y=(√5 + √4) (√6 - √5) (√7+ √3) 3.rezolvati ecuatile: a)4(x + 3) - 7x = 5(2 - x) + 17 b)5x - 7(x + 1) = 3(3 - 2x) c)2(x + 3) + 5(1 - 2x) = 2 - x - 3(x + 1) c)2(x + 3) + 5(1 - 2x) = 2 - x - 3(x + 1) d)3(x + 4) - 5(2x + 1) = 4(x + 3) - 6(2x + 3) 4.rezolcati ecuatiile: a) (2x + 1)² - 3(x +3)(x - 1) = (x - 2)² + 3 b) (3x - 1)² - 5(x + 3)(x - 3)= (2x + 1)² + 35 c) (x - 3)² + (x - 5)(x +3) = 2(x - 1)(x + 1) - 20 5.rezolvati ecuatiile: a)2{3(2x - 1) - 2[3(x + 4) - 2(x + 6)]} = 3[8 - 5(3x - 2)] - 7 b)3{2(3x + 2) - 3[2(3x + 5) - 3(x + 4)]} = 5[4 - 3(2x - 9)] - 41 in jumate de ora va roggg!!!!!!!!!!!!!