1a) KI + 1/2 Cl2 ---> KCl + 1/2 I2
b)166 g KI.......1/2*22,4 l Cl2
66,4 g KI.............x l Cl2 x = 4,48 l Cl2
2) Zn + 2 HCl ---> ZnCl2 + H2
65 g Zn.........1 mol H2
6,5 g Zn.........x moli H2 x = 0.1 moli H2
pV=nr moli * R * T => V = [0,1*0,082*(57+273)]/3 = 0,902 l H2
3)pOH = - lg [HO-] = - lg 10 la -2 => pOH = 2 - pt ca este baza
pH = 14 - pOH = 14-2 = 12
4)daca [H3O+]= 10 la -7 => pH neutru...adica 7