[tex] \frac{x-1}{2} + \frac{2x+1}{3} = \frac{1-2x+1}{6} [/tex]
[tex] \frac{3(x-1)+2(2x+1)}{6} = \frac{1-2x+1}{6} [/tex]
[tex] \frac{3x-3+4x+2}{6} = \frac{1-2x+1}{6} [/tex]
3x-3+4x+2=1-2x+1
3x+4x+2x=1+1+3-2
9x=3
x=[tex] \frac{3}{9} [/tex]
x=[tex] \frac{1}{3} [/tex] | => x ∈ Q
