Răspuns :
ΔABC, mas <B=90
BD _|_AC
BD-h
AD/DC=4
(AD+DC)/DC=4
AC/DC=4
20/DC=4
DC=20/4=5
AD=AC-DC
AD=20-5
AD=15
BD²= AD*DC
BD²= 15*5
BD= √75 =>BD=5√3
BD _|_AC
BD-h
AD/DC=4
(AD+DC)/DC=4
AC/DC=4
20/DC=4
DC=20/4=5
AD=AC-DC
AD=20-5
AD=15
BD²= AD*DC
BD²= 15*5
BD= √75 =>BD=5√3
AC=20
AD/DC=4 => AD=4DC
AD=AC-DC
AC-DC=4DC
AC=5DC=20
DC=4
Din teorema catetei:
BC²=AD*AC=4*20
BC=2√20
AD=20-4=16
AB²=AD*AC=16*20
AB=4√20
BD²=CB²-CD²=80-16=64
BD=8
AD/DC=4 => AD=4DC
AD=AC-DC
AC-DC=4DC
AC=5DC=20
DC=4
Din teorema catetei:
BC²=AD*AC=4*20
BC=2√20
AD=20-4=16
AB²=AD*AC=16*20
AB=4√20
BD²=CB²-CD²=80-16=64
BD=8