Răspuns :
a-4b+8c=25/ *3
3a-12b+24c=75
2a+b-3c=15
adunam ultimele doua relatii si obtinem
5a-11b+21c=90
2.
a+b+c+d+e=230
b=a+3
c=a+6
d=a+9
e=a+12
a+a+3+a+6+a+9+a+12=230
5a+30=230
5a=230-30
5a=200
a=40
b=43- nr prim
c=46
d=49
e=52
In ziua a II-a a citit un nr prim de pagini
3a-12b+24c=75
2a+b-3c=15
adunam ultimele doua relatii si obtinem
5a-11b+21c=90
2.
a+b+c+d+e=230
b=a+3
c=a+6
d=a+9
e=a+12
a+a+3+a+6+a+9+a+12=230
5a+30=230
5a=230-30
5a=200
a=40
b=43- nr prim
c=46
d=49
e=52
In ziua a II-a a citit un nr prim de pagini
1.
a -4b+8c=25 |*3
=>3a-12b+24c=75 +
2a+b-3c=15
Le adunam si obtinem:
5a-11b+21c=75+15=90
2.
In prima zi =n pagini
A doua zi a citit =n+3
a treia zi = n+6
a patra zi =n+9
a 5-a zi =n+12
=> 5n+3+6+9+12=230
n=200:5=40
=> in a doua zi a citit 43 pagini= numar prim
a -4b+8c=25 |*3
=>3a-12b+24c=75 +
2a+b-3c=15
Le adunam si obtinem:
5a-11b+21c=75+15=90
2.
In prima zi =n pagini
A doua zi a citit =n+3
a treia zi = n+6
a patra zi =n+9
a 5-a zi =n+12
=> 5n+3+6+9+12=230
n=200:5=40
=> in a doua zi a citit 43 pagini= numar prim