Răspuns :
A=(10*25+6)/25=256/25
orz= 1/4*256/25=64/25
porumb= 256/25-64/25=192/25
1/3*192/25=64/25
grau= 256/25-128/25=128/25
x%*128=64
x%=64/128
x%=0.5
suprafata cultivata cu grau este 50% din cea cultivata cu porumb
orz= 1/4*256/25=64/25
porumb= 256/25-64/25=192/25
1/3*192/25=64/25
grau= 256/25-128/25=128/25
x%*128=64
x%=64/128
x%=0.5
suprafata cultivata cu grau este 50% din cea cultivata cu porumb
10 intregi 6/25= 256/25- suprafata de teren
1/4 din 256/25= 1/4 * 256/25= 64/25-se cultiva orz
256/25-64/25= 192/25-restul
1/3 din 192/25= 1/3 * 192/25= 64/25 -se cultiva porumb
192/25-64/25= 128/25 -se cultiva grau
c)p% din 128/25= 64/25
p/100 *128/25=64/25
p/100=64/25 * 25/128
p/100= 1/2
p=100/2=50%
1/4 din 256/25= 1/4 * 256/25= 64/25-se cultiva orz
256/25-64/25= 192/25-restul
1/3 din 192/25= 1/3 * 192/25= 64/25 -se cultiva porumb
192/25-64/25= 128/25 -se cultiva grau
c)p% din 128/25= 64/25
p/100 *128/25=64/25
p/100=64/25 * 25/128
p/100= 1/2
p=100/2=50%