Răspuns :
Fie a si b aceste numere
a-b=1997
a:b=3rest 7⇒a=3b+7 (din teorema impartirii cu rest )
Avem o ecuatie doar in b
Obtinem :3b+7-b=1997⇒2b+7=1997⇒2b=1990⇒b=995
a=3b+7⇒a=3*995+7⇒a=2992
a-b=1997
a:b=3rest 7⇒a=3b+7 (din teorema impartirii cu rest )
Avem o ecuatie doar in b
Obtinem :3b+7-b=1997⇒2b+7=1997⇒2b=1990⇒b=995
a=3b+7⇒a=3*995+7⇒a=2992
x-y =1997
x:y=3 rest 7 =>x =3y+7
Deci: 3y+7-y=1997
2y=1990
y=995
x-y=1997=>x=1997+995=2992
x:y=3 rest 7 =>x =3y+7
Deci: 3y+7-y=1997
2y=1990
y=995
x-y=1997=>x=1997+995=2992