Răspuns :
(x-4)² = 4/9
(x-4)² -4/9=0
[(x-4)+2/3][(x-4)-2/3]=0
x-4+2/3=0 ∧ x-4- 2/3=0 aducem la acelasi numitor in fiecare caz
3x-12+2=0 ∧ 3x -12-2=0
3x-10=0 3x-14=0
3x=10 3x=14
x= 10/3 x= 14/3
(x-4)² -4/9=0
[(x-4)+2/3][(x-4)-2/3]=0
x-4+2/3=0 ∧ x-4- 2/3=0 aducem la acelasi numitor in fiecare caz
3x-12+2=0 ∧ 3x -12-2=0
3x-10=0 3x-14=0
3x=10 3x=14
x= 10/3 x= 14/3
(x-4)²=a²-2ab+b²=x²-8x+16=0,4
x²-8x+16=0,4
x²-8x+15,6=0
Δ=64-62.4=1.6
x1,2=8+-√1.6/2
x1=8+√1.6/2
x2=8-√1.6/2
x²-8x+16=0,4
x²-8x+15,6=0
Δ=64-62.4=1.6
x1,2=8+-√1.6/2
x1=8+√1.6/2
x2=8-√1.6/2