Răspuns :
Bd=bc-dc
bd=25-16=9
=>BD=9cm
Cu teorema catetei aflam Abla2=bc ori bd
abla2=25 ori 9
ab la2=225
ab=15
Cu teorema lui pitagora aflam ac
Ac^2=Bc2-Ab^2
Ac^2=625-225
Ac^2=400
Ac=20
bd=25-16=9
=>BD=9cm
Cu teorema catetei aflam Abla2=bc ori bd
abla2=25 ori 9
ab la2=225
ab=15
Cu teorema lui pitagora aflam ac
Ac^2=Bc2-Ab^2
Ac^2=625-225
Ac^2=400
Ac=20
bd=BC-CD=25-16=9 cm
in ΔABD : AB²=BD²+AD²=81+AD²
In ΔADC: AC²=AD²+DC²=AD²+256
=>Daca le adunam: AB²+AC²=2AD²+81+256 (1)
In ΔABC: AB²+AC²=BC²=625 (2)
=> din (1) si (2) Avem:
2AD²+337=625
2AD²=288
AD²=144
AD=12
=> AB²=81+144=225
AB=15
AC²=144+256=400
AC=20
in ΔABD : AB²=BD²+AD²=81+AD²
In ΔADC: AC²=AD²+DC²=AD²+256
=>Daca le adunam: AB²+AC²=2AD²+81+256 (1)
In ΔABC: AB²+AC²=BC²=625 (2)
=> din (1) si (2) Avem:
2AD²+337=625
2AD²=288
AD²=144
AD=12
=> AB²=81+144=225
AB=15
AC²=144+256=400
AC=20