Răspuns :
5z+3x+4y=59-27
= 32
b)x-2y=+13=52,
x-2y=52-13
= 39
3x-6y+1= 2x39+1
= 78+1
=79
= 32
b)x-2y=+13=52,
x-2y=52-13
= 39
3x-6y+1= 2x39+1
= 78+1
=79
a)3x+4y+5z+27=59
3x+4y+5z=59-27
3x+4y+5z=32
5z+3x+4y=32
b)x-2y+13=52
x-2y=52-13
x-2y=39
3x-6y+1=3(x-2y)+1
=3*39+1
=117+1
=118
3x+4y+5z=59-27
3x+4y+5z=32
5z+3x+4y=32
b)x-2y+13=52
x-2y=52-13
x-2y=39
3x-6y+1=3(x-2y)+1
=3*39+1
=117+1
=118