Răspuns :
a)[(x+√2)-2√2][(x+√2)+2√2]= (x-√2)(x+3√2)
b)[(x-√5)-3√5][(x-√5)+3√5]=(x-4√5)(x+2√5)
c)√12=2√3
[(2x+√3)-2√3][(2x+√3)+2√3]=(2x-√3)(2x+3√3)
b)[(x-√5)-3√5][(x-√5)+3√5]=(x-4√5)(x+2√5)
c)√12=2√3
[(2x+√3)-2√3][(2x+√3)+2√3]=(2x-√3)(2x+3√3)
DFHTRFHGfydghfg gata,acum dai lu miky "raspunsul cel mai bun" :)