Răspuns :

Miky93id
[(4x+1)-(2x+3)][(4x+1)+(2x+3)]=

=(4x+1-2x-3)(4x+1+2x+3)=

=(2x-2)(6x+4)=

=2(x-1)(3x+2)
Tstefanid
(4x + 1)² - (2x + 3)² = 16x² + 8x + 1 - 4x² - 12x - 9 =

12x² -4x - 8 = 4(3x² - x - 2) =

= 4(3x² - 3x + 2x - 2) = 

= 4(3x(x - 1) + 2(x - 1)) =

= 4(x - 1)(3x + 2)


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