cum se rezolva? A) (12supra35-7supra20)*(-1-1supra6)= B)(6supra32+5supra24)*30supra38-1supra8= C)3-2:(5supra8*12supra15)+(1supra3)la puterea a2a D)(1supra4+0,67+5supra2):0,2
A) Aducem la acelasi numitor in prima paranteza :140 (12*4/140-7*7/140)*(-6-1/6) (48-49)/140*(-7/6) (-1/140)*(-7/6) 1/120 B) aducem la acelasi numitor in prima paranteza:96 (18+20)/96*3/38-1/8 38/96*3/38-1/8 1/32-1/8 -3/32 C) 3-2:(1/2*1)+1/9 3-1+1/9 2+1/9 (18+1)/9 19/9 D) (1/4+67/100+5/2)*10/2 (25+67+250)/100*5 342/100*5 324/20 171/10
