Răspuns :

Miky93id
(3x+2)/3 + (9+x)/9=5  aducem la acelasi numitor

9x+6+9+x=45

10x+15=45

10x=45-15

10x=30
x=3
Crush19id
[tex] \frac{3x+2}{3} + \frac{9+x}{9} [/tex] =5

amplificam prima fractie cu 3 =>

[tex] \frac{9x+6}{9} + \frac{9+x}{9} [/tex] =5

[tex] \frac{10x+15}{9} =5

10x+15=9*5

10x+15=45  /-15

10x=30    /:10

x=3

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