Răspuns :
la prima paranteza puterile se inmultesc si o sa fie 25*4 = 100
deci ramane [1 / 3 ]^100
0,(3)^99= [1/3]^99
[1/3]^100 : [1/3]^99 ( puterile se scad ) = [1/3 ]^1
deci ramane [1 / 3 ]^100
0,(3)^99= [1/3]^99
[1/3]^100 : [1/3]^99 ( puterile se scad ) = [1/3 ]^1
[1/3]^25.100(asta este puterea) :[1/3}^99
0,(3)=3/9=1/3
(1/3)^100-99=(1/3)la puterea 1
0,(3)=3/9=1/3
(1/3)^100-99=(1/3)la puterea 1