1) 12-6·2=12-12=0
2) [tex] \frac{50}{100} [/tex] · x=10 deci x=[tex] \frac{10*100}{50} [/tex] x=20
3) 8
4) Arie romb= [tex] \frac{d1 * d2}{2} [/tex] = [tex] \frac{6*8}{2} [/tex] = 24
5)Tetraedrul regulat are toate muchiile egale deci suma= 6·latura=6·8=48
6) 100-(27+15+45) =100-87=13
