Răspuns :

[tex]x+\dfrac{1}{\sqrt3}+2+\sqrt3 = 2-x\\ x+\dfrac{\sqrt3}{3}+2+\sqrt3 = 2-x | \cdot 3\\ 3x+\sqrt3+6+3\sqrt3=6-3x\\ 3x+3x=6-\sqrt3-6-3\sqrt3\\ 6x=-4\sqrt3\\ x=-\dfrac{4\sqrt3}{6}=-\dfrac{2\sqrt3}{3}[/tex]

Sper că e bine.