Construiesc AD perpendicular pe BC In trg ABD dreptunghic isoscel (AD=BD=x) aplic T Pitagora x^2+x^2=(3V2)^2=18 ⇒ 2x^2=18⇒ x^2=9⇒ x=3 A trg =BC*AD/2=4V3*3/2=6V3 cm^2 Stiind aria pot sa aflu inaltime corespunzatoare laturii AB (CE) A trg=6V3 cm^2=AB*CE/2 ⇒ CE=12V3/AB=12V3/3V2=4V3/V2=4V6/2=2V6 cm
