Răspuns :

[tex]2\sqrt2-3<0\Rightarrow |2\sqrt2-3|=3-2\sqrt2[/tex]

[tex]b=(1+\sqrt2)^2=3+2\sqrt2[/tex]

[tex]m_g=\sqrt{ab}=\sqrt{(3-2\sqrt2)(3+2\sqrt2)}=\sqrt{9-8}=1[/tex]
Petrwid
(2√2)²=8
3²=9⇒se inverseaza numerele astfel din 2√2-3 devine 3-2√2
media geometrica= √axb
axb= 3-2√2 x 1+2√2+2
axb = (3-2√2)(3+2√2)
a x b=3²-2√2²
a x b= 9-8
a x b=1
media geometrica= √1=1

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