Răspuns :
cele 2 rezistoare sun legate in serie Rs=1+1=2, si toate 3 in paralel
1/R=1/2+1+1/2⇒R=0.5 ohmi
I=E/(R+r)= 4.5/1=4.5 A
U=RI=0.5*4.5=2.25 V
1/R=1/2+1+1/2⇒R=0.5 ohmi
I=E/(R+r)= 4.5/1=4.5 A
U=RI=0.5*4.5=2.25 V
[tex] \frac{1}{R} = \frac{1}{2} +1+ \frac{1}{2} =2[/tex]
Re=1/2=0.5 ohmi
[tex]I= \frac{E}{R+r} = \frac{4.5}{0.5+0.5} =4.5 A [/tex]
U=RI=0.5*4.5=2.25 V
Re=1/2=0.5 ohmi
[tex]I= \frac{E}{R+r} = \frac{4.5}{0.5+0.5} =4.5 A [/tex]
U=RI=0.5*4.5=2.25 V