Răspuns :

XAndiid
1*(x-1) +1*(x+1)=2x
x-1+x+1=2x
2x=2x  Adevarat
Itacabiid
[tex] \frac{1}{x} + \frac{1}{x-1} = \frac{2}{x+1}
 numitorul comun este x(x+1)(x-1)
[tex] \frac{(x+1)(x-1)+x+1}{x(x+1)(x-1)} = \frac{x-1}{x(x+1)(x-1)} [/tex]
x+1=0
x= -1

ID Alte intrebari