Răspuns :

Vasileandrei49id
1,(23)+1,2(3)=2,46(56)
ma=2,46(56)/2=1,23(28)
Miky93id
1,(23)= 1 intreg  23/99=  122/99

1,2(3)= 1 intreg (23-2)/90 = 1 intreg 21/90 = 1 intreg 7/30 = 37/30

ma= (a+b)/2

=(122/99 + 37/30)/2   aducem la acelasi numitor in paranteza (2970)=

=(362 340+ 109 890)/ 2970 /2 =

=472 230/2970/2=

=472 230/2970 * 1/2=

=263 115 /2970=

=79,5

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