Δ = b² -4ac = 9 - 4 · 18 · (-10) = 9 + 720 = 729 > √Δ = 27
[tex] x_{1} [/tex] = [tex] \frac{3+27}{36} = \frac{30}{36} = \frac{5}{6}[/tex]
[tex] x_{2} = \frac{3-27}{36} = - \frac{24}{36} = - \frac{2}{3} [/tex]
18x² -3x-10 = 18 ·( x-x1) · ( x-x2) = 18 ( x-[tex] \frac{5}{6} [/tex]) · (x+ [tex] \frac{2}{3} [/tex])
= ( 6x - 5 )( 3x + 2)
