Răspuns :

Crisforpid
Faci n = 1 => [tex] z_{2} = \sqrt{3+ \sqrt{3} } [/tex];
Faci n = 2 => [tex] z_{3} = \sqrt{3+ \sqrt{3+ \sqrt{3} } } ;[/tex]
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Pana ajungi la n = 2013.

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