obs.4x²-4x+1=(2x-1)(2x-1) ⇒ [(2x-1)(2x-1)]/[x(2x-1)]·[3(2x-1)]/[2(4x²-1)] se simplifica in prima fractie cu 2x-1⇒ (2x-1)/x·3(2x-1)/2(2x-1)(2x+1)⇒se simplifica cu 2x-1⇒ (2x-1)/x·3/2(2x+1)⇒ 3(2x-1)/2x(2x+1) conditia x≠0 si x≠ -1/2 2x-1=0 ⇒ 2x=1 ⇒ x=1/2
