Răspuns:
x³+3x²-6x-8=
(x³-8)+(3x²-6x)=
(x-2)(x²+2x+4)+3x(x-2)=
(x-2)(x²+2x+4+3x)=
(x-2)(x²+5x+4)=
(x-2)((x²+x)+(4x+4))=
(x-2)[x(x+1)+4(x+1)]=
(x-2)(x+1)(x+4)
Explicație pas cu pas:
