Salut! ♡
a+(a+1)+(a+2)+(a+3).....(a+2016)
=2017²⁰¹⁸
=a+a+a+...+a (2017 de a) + 1+2+3.....+2016
=2017²⁰¹⁸
2017×a+ 2016×2017/2= 2017²⁰¹⁷×2017|:2017
a+1018= 2017²⁰¹⁷
a= 2017²⁰¹⁷-1018
a+1= 2017²⁰¹⁷-1017
a+2= 2017²⁰¹⁷-1016
.............
a+2014= 2017²⁰¹⁷-1018+2014
=2017²⁰¹⁷-1006
a+2015=2017²⁰¹⁷-1007
a+2016= 2017²⁰¹⁷-1008
2017²⁰¹⁸=(2017²⁰¹⁷-1008)+(2017²⁰¹⁷-1007)+(2017²⁰¹⁷-1006)+.....+(2017²⁰¹⁷-1006)++(2017²⁰¹⁷-1007)+(2017²⁰¹⁷-1008)
sunt 2017 numere consecutive
suma este 2017²⁰¹⁷ de 2017 ori =>
=> 2017²⁰¹⁷×2017= 2017²⁰¹⁸.
