Răspuns: [tex]\red{ \underline{ \: \bf 70 \: }}[/tex]
Am atașat si imaginea cu exercițiul complet
[tex]\bf \bf 10 \cdot\Big \{18^{2}:324 + 2\cdot\big[(2^{2}\cdot3)^{15}:(2^{29}\cdot3^{15})+1^{24}\big]\Big \} =[/tex]
[tex]\bf 10 \cdot \Big\{324:324 + 2\cdot\big[(2^{2\cdot15} \cdot3^{15}):(2^{29}\cdot3^{15})+1\big]\Big \} =[/tex]
[tex]\bf 10 \cdot \Big\{1 + 2\cdot\big[(2^{30} \cdot3^{15}):(2^{29}\cdot3^{15})+1\big]\Big \} =[/tex]
[tex]\bf 10 \cdot\big[1+ 2\cdot(2^{30 - 29} \cdot3^{15 - 15}+1)\big]=[/tex]
[tex]\bf 10 \cdot\big[1+ 2\cdot(2^{1} \cdot3^{0}+1)\big]=[/tex]
[tex]\bf 10 \cdot\big[1+ 2\cdot(2 \cdot 1+1)\big]=[/tex]
[tex]\bf 10 \cdot\big[1+ 2\cdot(2+1)\big]=[/tex]
[tex]\bf 10 \cdot\big(1+ 2\cdot 3 \big)=[/tex]
[tex]\bf 10 \cdot\big(1+ 6 \big)=[/tex]
[tex]\bf 10 \cdot 7 =[/tex]
[tex]\red{ \underline{ \: \bf 70 \: }}[/tex]
[tex]==pav38==[/tex]
