Răspuns:
[tex]\bf \bigg[0,(3)+1,(3):1\dfrac{7}{9}\bigg] :\bigg(1+\dfrac{1}{12}\bigg)=[/tex]
[tex]\bf \bigg[\dfrac{3}{9}+\dfrac{13-1}{9} :\dfrac{9\cdot1+7}{9}\bigg] :\bigg(\dfrac{^{^{12)}}1~}{1}+\dfrac{1}{12}\bigg)=[/tex]
[tex]\bf \bigg[\dfrac{3^{(3}~}{9}+\dfrac{12}{9} :\dfrac{16}{9}\bigg] :\bigg(\dfrac{12}{12}+\dfrac{1}{12}\bigg)=[/tex]
[tex]\bf \bigg(\dfrac{1}{3}+\dfrac{\not12}{\not9} \cdot\dfrac{\not9}{\not16}\bigg) :\dfrac{13}{12}=[/tex]
[tex]\bf \bigg(\dfrac{1}{3}+\dfrac{3}{1} \cdot\dfrac{1}{4}\bigg) :\dfrac{13}{12}=[/tex]
[tex]\bf \bigg(\dfrac{^{^{4)}} 1~}{3}+\dfrac{^{^{3)}} 3~}{4} \bigg)\cdot\dfrac{12}{13}=[/tex]
[tex]\bf \bigg(\dfrac{4}{12}+\dfrac{9}{12} \bigg)\cdot\dfrac{12}{13}=[/tex]
[tex]\bf \dfrac{\not13}{\not12} \cdot\dfrac{\not12}{\not13}= \red{\boxed{\bf ~1~}}[/tex]
