Răspuns :
Răspuns:
[tex]\bf a) ~2^{76} + 2^{78} + 2^{80} =[/tex]
[tex]\bf 2^{76}\cdot \big(2^{76-76} + 2^{78-76} + 2^{80-76}\big)=[/tex]
[tex]\bf 2^{76}\cdot \big(2^{0} + 2^{2} + 2^{4}\big)=2^{76}\cdot \big(1 + 4 +16\big)=[/tex]
[tex]\blue{\underline{~\bf 2^{76}\cdot21~}}[/tex]
[tex]\bf b) ~3\cdot5^{47} + 2\cdot 5^{48} + 6\cdot5^{49} =[/tex]
[tex]\bf 5^{47}\cdot \big(3\cdot5^{47-47} + 2\cdot5^{48-47} +6\cdot5^{49-47}\big)=[/tex]
[tex]\bf 5^{47}\cdot \big(3\cdot5^{0} + 2\cdot5^{1} +6\cdot5^{2}\big)=[/tex]
[tex]\bf 5^{47}\cdot \big(3\cdot 1 + 2\cdot5 +6\cdot 25\big)= 5^{47}\cdot \big(3+10+150\big)=[/tex]
[tex]\purple{\underline{~\bf 5^{47}\cdot163~}}[/tex]
[tex]\bf c) ~13^{14}\cdot 3 -13^{13}\cdot2- 13^{12} =[/tex]
[tex]\bf 13^{12}\cdot \big(13^{14-12}\cdot 3 -13^{13-12}\cdot2- 13^{12-12}\big)=[/tex]
[tex]\bf 13^{12}\cdot \big(13^{2}\cdot 3 -13^{1}\cdot2- 13^{0}\big)=[/tex]
[tex]\bf 13^{12}\cdot \big(169\cdot 3 -13\cdot2- 1\big)=[/tex]
[tex]\bf 13^{12}\cdot \big(507 -26- 1\big)=[/tex]
[tex]\red{\underline{~\bf 13^{12}\cdot 480~}}[/tex]
Sper să fie de folos răspunsul meu chiar dacă vine cu 4 zile întârziere față de când ai postat exercițiul.
Baftă multă !