9.9
cu b)
E.M.C.
BaCl2 + K2SO4 --> BaSO4 + 2KCl
E.I.C.
Ba²⁺ + 2Cl⁻ + 2K⁺ + (SO4)²⁻ --> Ba²⁺ + (SO4)²⁻ + 2K⁺ + 2Cl⁻
E.I.R.
Ba²⁺ + (SO4)²⁻ --> BaSO4
md = 50g,
V.apa = 150 mL ,ro = 1 g/mL
=> m.apa = roxV = 150x1 = 150 g
ms = md + m.apa = 150 + 50 = 200 g
w% = mdx100/ms
= 50x100/200 = 25% , b)