Răspuns:
Bună,
[tex]a) \sqrt{2} + \sqrt{2} = 2 \sqrt{2} \\ b)2 \sqrt{5} + 3 \sqrt{5} = 5 \sqrt{5} \\ c) \sqrt{3} + ( - \sqrt{3} ) = \sqrt{3} - \sqrt{3} = 0 \\ d) \sqrt{5} - \sqrt{5} = 0 \\ e)7 \sqrt{7} - 2 \sqrt{7} = 5 \sqrt{7} \\ f) \sqrt{6} - 3 \sqrt{6} = - 2 \sqrt{6} \\ g) \sqrt{ 6} + 2 \sqrt{6} + 3 \sqrt{6} = 6 \sqrt{6} \\ h)4 \sqrt{10} - 3 \sqrt{10} - 3 \sqrt{10} = - 2 \sqrt{10 } \\ i)4 \sqrt{2} + ( - 3 \sqrt{2} ) + ( - 5 \sqrt{2} ) = \\ 4 \sqrt{2} - 3 \sqrt{2} - 5 \sqrt{2} = - 4 \sqrt{2} \\ j)2 \sqrt{3} - ( - 3 \sqrt{3} ) - ( - 4 \sqrt{3} ) = \\ 2 \sqrt{3 } + 3 \sqrt{ 3} + 4 \sqrt{3} = 9 \sqrt{3} \\ k)8 \sqrt{5 } - \sqrt{5} - \sqrt{5} = 6 \sqrt{5} [/tex]
Sper că te-am ajutat.
