[tex]102+\left\{\left[25\times \:4-\left(3\times \:23+3\times \:10\right)\right]\times \:102\right\}\div \:2 = [/tex]
[tex]25\times \:4-\left(3\times \:23+3\times \:10\right) =25\times \:4-99 =100-99 = 1[/tex]
[tex]=102+1\times \:102\div \:2 [/tex]
[tex]=102+51 =153[/tex]
Sper că te-am ajutat!
Succes!