Răspuns :

a) 46:23+{78-3×[(15+7×5]-3×7 = 46:23+{78-3×[(15+35]-3×7= 46:23+[78-3×( 50-3×7) = 46: 23 + [78-3* (50 - 21)]= 46:23+(78-3*29)= 46:23+(78-87) = 46:23+ (-9)=

= 2+ (-9) = -7

b) 9×{8+7×[6+5×(4+3×(2+1))]}: (1+2+3...+9)= 9×{8+7×[6+5×(4+3×3]}: (1+2+3...+9)=

=9×{8+7×[6+5×(4+9)]}: (1+2+3...+9)= 9×[8+7×(6+5×13)]: (1+2+3...+9)= 9×[8+7×(6+65)]: (1+2+3...+9)= 9×(8+7×71): (1+2+3...+9)= 9×(8+497): (1+2+3...+9)=

=9x505:(1+2+3+...+9)= 9x505:45=4545:45=101

c) 1+2×{3+4:[5-6:(7-8:(9-1))]}=1+2×{3+4:[5-6:(7-8:8)]=1+2×{3+4:[5-6:(7-1)]}=1+2×[3+4:(5-6:6)]=1+2×[3+4:(5-1)]= 1+2x(3+4:4)= 1+2x(3+1)=1+2x4=1+8=9

Folosim ordinea operațiilor

A)2+ { 75 x [ (15+35) -21 ]} = 2+ [75x 50 -21]= 2+ (3750-21) =2+ 3729 = 3731
B) 9x { 15 x [ 11 x (7 x 3 )]} : 45 = 8x {15x[11x 21]} : 45 = 9x [15x ( 11x21)] :45 = 9x ( 15 x 231):45= 9x 3465 :45 = 31185:45 = 693
C) 3x { 7: [-1: (-1:8)]}= 3x [7:(-1: aici chiar nu îmi dai seama …