[tex]\it g)\ \Big |\dfrac{x}{2}-\dfrac{x-3}{4}\Big|=2 \Rightarrow \dfrac{x}{2}-\dfrac{x-3}{4}=\pm2|_{\cdot4} \Rightarrow 2x-x+3=\pm8 \Rightarrow \\ \\ \\ \Rightarrow x+3\in\{-8,\ \ 8\}|_{-3} \Rightarrow x\in\{-11,\ \ 5\}[/tex]
[tex]\it h)\ \ |(x-2)(4-y)|=0 \Rightarrow \begin{cases} \it x-2=0 \Rightarrow x=2\\ \\ sau\\ \\ \it4-y=0 \Rightarrow y=4\end{cases}[/tex]
