Răspuns:
a) 1 < √n < 2
√1 < √n <√4
R: n= √3 , √2
b) 2 ≤ √n < 3
√4 ≤ √n < √9
R: n=√8, √7, √6, √5, √4
c) 3< √n ≤ 4
√ 9 < √ n ≤ √16
R: n=√16, √15, √14, √13, √12, √11, √10
d) 4 ≤ √ n ≤ 5
√16 ≤ √ n ≤ √25
R: n=√25,√24,√23,√22,√21,√20,√19,√18,√17,√16,
Sper ca te-am ajutat, succes in viitor cu algebra
<3
