Răspuns :
(T.F.A)ΔAMB≈ΔDMC⇔MD/MD+12=MC/MC+15=18/24=3/4⇔4MC=3MC+45⇔MC=45
4MD=3MD+36⇔MD=36
PΔMAB=12+36+15+45+24=132cm
sper ca team ajutat!
(T.F.A)ΔAMB≈ΔDMC⇔MD/MD+12=MC/MC+15=18/24=3/4⇔4MC=3MC+45⇔MC=45
4MD=3MD+36⇔MD=36
PΔMAB=12+36+15+45+24=132cm
sper ca team ajutat!