Răspuns :

[tex]\it h)\ \Big(\dfrac{22}{3}\Big)^5:\Big(\dfrac{11}{9}\Big)^5= \Big(\dfrac{22}{3}:\dfrac{11}{9}\Big)^5= \Big(\dfrac{22}{3}\cdot\dfrac{9}{11}\Big)^5= \Big(\dfrac{198}{33}\Big)^5=6^5=7776\\ \\ \\ i)\ \Big(\dfrac{3}{4}\Big)^{14}: \Big(\dfrac{9}{16}\Big)^6= \Big[\Big(\dfrac{3}{4}\Big)^2\Big]^{7}: \Big(\dfrac{9}{16}\Big)^6= \Big(\dfrac{9}{16}\Big)^{7}: \Big(\dfrac{9}{16}\Big)^6= \dfrac{9}{16}[/tex]

[tex]\it j)\ 20\%\ din\ 250=\dfrac{20}{100}\cdot240=2\cdot24=48[/tex]