[tex]\it a)\ \ \dfrac{1}{2}\sqrt{24}=\dfrac{1}{2}\sqrt{4\cdot6}=\dfrac{1}{2}\cdot2\sqrt{6}=\sqrt6\\ \\ \\ h)\ \ -\dfrac{1}{6}\sqrt{18}=-\dfrac{1}{6}\sqrt{9\cdot2}=-\dfrac{1}{\not6_2}\cdot\not3\sqrt{2}=-\dfrac{\sqrt2}{2}\\ \\ \\ g)\ \ -5\sqrt{20}=-5\sqrt{4\cdot5}=-5\cdot2\sqrt5=-10\sqrt5[/tex]
