Răspuns:
MCO2=12+2×16=44g/mol
44 g CO2.... .....12 g C
5,28g CO2........ x g C
x=5,28×12/44= 1,44 g C
MH2O=2×1+16=18g/mol
18 g H2O ............2 g H
1,62 g H2O ........ y g H
y =1,62×2/18= 0,18 g H
1,44+0,18= 1,62 g CH
compoziția procentuală CH
1,62 g CH ................1,44 g C........... 0,18 g H
100% CH.................z%C....................t%H
z=100×1,44/1,62= 88,89% C
t=100×0,18/1,62= 11,11% H
Explicație:
