Răspuns:
4b: [8+8(8^2+8^98:8^96)]:129= [8+8(64+8^2)]:129= (8+8*128):129= 1032:129=8
5a: a= (3^2)^3*3^4:3^4=3^6*3^4:3^4=3^10:3^4=3^6
b=27=3^3
=> a>b
5b: 11\3 (3*6+5)\6 (33-3)\9
22\6 23\6 30\9=10\3
22\6 23\6 20\6
20\6, 22\6, 23\6
Sper că te-am putut ajuta :))
