Răspuns:
[tex]a=\sqrt{18}-\sqrt{32}-\sqrt{50}+\sqrt{2}+\sqrt{72}=\\=3\sqrt{2}-4\sqrt{2}-5\sqrt{2}+\sqrt{2}+6\sqrt{2}=\sqrt{2}[/tex]
[tex]b=\sqrt{12}*(\sqrt{24}+\sqrt{54})-\sqrt{3*6}-\sqrt{40}:\sqrt{5}=\\=2\sqrt{3}*(2\sqrt{6}+3\sqrt{6})-\sqrt{18}-2\sqrt{10}:\sqrt{5}=\\=4\sqrt{18}+6\sqrt{18}-6\sqrt{3}-2\sqrt{2}=10*3\sqrt{2}-3\sqrt{2}-2\sqrt{2}=25\sqrt{2}[/tex]
media geometrica= [tex]\sqrt{25\sqrt{2}*\sqrt{2}}=5\sqrt{2}[/tex]
Explicație pas cu pas:
