Răspuns:
a)AB=√(xA-xB)²+(yA-yB)²
1.AB=√(3-(-1))²+(1-4)²=
√(3+1)²+(-3)²=√(4²+9)=√(16+9)=√25=4
2,AB=√(2-0)²+(0-3)²=√(2²+(-3))²=√(4+9)=√13
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b)Formula
AB: (y-yA)/(yB-yA)=(x-xA)/(xB-xA)
1.AB=(y-1)/(4-1)=(x-3)/(-1-3)
(y-1)/3=(x-3)/(-4)
y-1= -3/4(x-3)
y= -3x/4+9/4+1
y= -3x/4+13/4
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2.(y-0)/(3-0)=(x-2)/(0-2)
y/3=(x-2)/(-2)
y=-3/2(x-2)
y= -3x/2+3
Explicație pas cu pas:
