Răspuns:
Explicație:
21,3 g Cl
react. cu Fe
16,25g sare
randament =?
xg 16,25g
3Cl2 + 2Fe=2FeCl3
3.71g 2. 162,5g
x= 213 . 16,25 : 325 =10,65 g clor consumat in reactie
randament= mp.100 : mt
= 10,65 .100 : 21,3= 50%
MCl2= 2 . 35,5 =71-------> 71g/moli
MFeCl3= 56 + 3.35,5= 162,5 -------> 162,5g/moli