Răspuns:
Triunghiul ABC, masura A =90, masura B=30
Rezulta masura C =180-90-30=60
Teorem medianei AM = BC /2
BC = 2 AM
BC = 2* 12
BC = 24
Sin B = AC / BC
Sin 30 = AC / BC
1/2 = AC/24
AC = 24/2
AC = 12
Cos B = AB / BC
Cos 30 = AB / BC
Radical3/2 = AB/24
AB= 24 * radical 3 / 2
AB=12 rad 3
Triunghiul ADC, masura unghiului C = 60 grade
Sin C = AD/AC
Radical3/2 = AD/12
AD = (12*radical3)/2
AD = 6* radical 3
Cos C = CD/AC
Cos 60 = CD/12
1/2=CD/12
CD=12/2
CD=6
BC= BD +DC
BD = BC-DC
BD = 24-6
BD =18
P=AB+BC+AC
P=12 rad 3 + 24+12
P= 36+ 12rad3
