Răspuns :

T= 273,15 K

P= 1 atm

mO2=64g

μO2=32g/mol

R=0,082 l*atm/mol*k

P*V=σ*R*T

V=σ*R*T/P

σO2=mO2/μO2=64/32=2moli

VO2=2*0.082*273,15/1

VO2=44,79L=44,79[tex]dm^{3}[/tex]